0=y^2+2y-118

Solution for 0=y^2+2y-118 equation:

0=y^2+2y-118

We move all terms to the left:

0-(y^2+2y-118)=0

We add all the numbers together, and all the variables

-(y^2+2y-118)=0

We get rid of parentheses

-y^2-2y+118=0

We add all the numbers together, and all the variables

-1y^2-2y+118=0

a = -1; b = -2; c = +118;
Δ = b2-4ac
Δ = -22-4·(-1)·118
Δ = 476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{476}=\sqrt{4*119}=\sqrt{4}*\sqrt{119}=2\sqrt{119}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{119}}{2*-1}=\frac{2-2\sqrt{119}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{119}}{2*-1}=\frac{2+2\sqrt{119}}{-2}
$